Today in Honors Physics, we started class by going over our detailed analysis #1-16. We also found out what really happened to Stonehenge! After this, we worked on the rest of the detailed analysis, using the key to help us. When we got to #38 in the detailed analysis, Coats-Haan gave us notes on the horizontal range equation. Then we continued working on the rest of detailed analysis packet. If we did not finish this in class, we needed to finish it for homework.
QOD: To determine if the ball in today’s problem reaches its maximum height before or after it reaches the edge of the cliff, you first had to calculate the time required to reach the top of the ball’s trajectory, which was calculated using the first equation. This turned out to be 0.587 seconds. Next, you needed to calculate the horizontal distance the ball travels during the time it takes to reach the peak. Because the horizontal component is uniform motion, you can use the equation x = vt. The resulting horizontal distance is 5.84 m. The horizontal distance from the initial x position to the edge of the cliff is 5.00 m. So, the ball reached maximum height 0.84 m past the edge of the cliff.
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