10/11Miley

We first checked problems from Pg. 54 57-62 and answered any questions people had. One of the problems we went over was #62.The question was a helicopter is lifting off the ground and is moving vertically upward. The graph is shown vertically velocity v,y versus time. How high is the helicopter after 12.0 s hasve elapsed? Mrs. Coats-Haan saids the easiest way to solve this problem was to find the velocity and time of each vector. Then you mulitply the velocity and time to figure out the distance. Then you add the 3 quanities together to get your total distance. We also could have started our linear motion review packet and our acceleration vs. time graph for homework as well. During class, we had the option to either redo last night's homework problems, start/finish our review guide, and/or start/finish our acceleration vs. time graph packet. When acceleration and velocity are the same, it means that the direction will be left or right(depending on if it's positive or negative) and it will speed up. If acceleration and velocity aren't the same, the direction will be either right or left(depending on the velocity sign) and it will slow down.